5a^2=-8+14a

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Solution for 5a^2=-8+14a equation:



5a^2=-8+14a
We move all terms to the left:
5a^2-(-8+14a)=0
We add all the numbers together, and all the variables
5a^2-(14a-8)=0
We get rid of parentheses
5a^2-14a+8=0
a = 5; b = -14; c = +8;
Δ = b2-4ac
Δ = -142-4·5·8
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-6}{2*5}=\frac{8}{10} =4/5 $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+6}{2*5}=\frac{20}{10} =2 $

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